text:
User:Naruemol.p

Each student answer the questions on his or her wikiversity User page:

1. How do you open the Select Pane in PowerPoint 2007?

A: Go to Home/Editing/Select/Selection Pane

2. In PowerPoint 2007, how do you change the maximum number of Undoes to 30?

A: Left click on the Customize Quick Access Toolbar in the top left side of the window/More Commands/Advanced/Editing options, then change the maximum number of undos to 30.

3. How do you save a PowerPoint 2007 file as a web page?

A: Click office button/Save As/Save as type/Web page

4. How do you change the colour of a SmartArt object in PowerPoint 2007?

A: Click on the Block list, then go to Format/Shape Styles and select the colour that you want.

5. In PowerPoint 2007, how do you include slide numbers on every slide?

A: Insert tab/text, and click Slide Number.

6. How do you change the slide orientation of a PowerPoint 2007 presentation to portrait?

A: Go to Design/Page Setup/Slide Orientation/Portrait.

7. How do you modify a textbox so that its text shrinks to fill the space in the shape in PowerPoint 2007?

A: Right click on the text in the textbox/Format Text Effects/Text Box/Autofit, then select Resize shape to fit text.

8. How do you add a circle shape to a slide in PowerPoint 2007?

A: Go to Insert/Illustrations/Shapes/Circle.

9. On the Ribbon in PowerPoint 2007, how do you change text in the textbox to WordArt?

A: Go to Format/WordArt Sytles then select the sytle that you want.

10. How do you open a current presentation in PowerPoint 2007?

A: Go to Slide Show tab/ under the Start Slide Show group/select From Current Slide

11. How do you turn on the grids in PowerPoint 2007?

A: Go to View, Show/Hide, then select Gridines.

12. What will allow you to quickly make a PowerPoint presentation as quickly as you can type?

A: Press F5

13. How do you go to Handout Master in PowerPoint 2007?

A: Go to View/Presentation Views/Handout Master

14. What does the Contrast function do in PowerPoint 2007?

A: To adjust a picture's relative lightness (brightness), the difference between its darkest and lightest areas (contrast), and the transparency of one of its colours.

15. In PowerPoint 2007, how do you print out the slide you are currently looking at?

A: Go to office button/Print/Print range/Current slide

Homework 5
Computer Brand: ACER (MPC ASM3800-752G7500M/C002)

CPU: Intel Core 2 Duo E7500 2.93 GHz.

sSpec Number: SLB9Z

CPU Speed: 2.93 GHz

PCG: 06

Bus Speed: 1066 MHz

Bus/Core Ratio: 11

L2 Cache Size: 3 MB

L2 Cache Speed: 2.93 GHz

RAM: 2048/1066

HDD(GB): 500/7200 SATA

ODD: DVD-RW

VGA: Intel G43 on-die graphics solution

Moniter: LCD 23'' ACER T230HBMIDH

'''

Homework 4
'''

1.What are MMOGs and how do they differer from regular video games?

MMOGs or Massively Multiplayer Online Games is a video game played on the internet. MMOGs differ from other video games in terms of the number of the players. It is capable of supporting hundreds or thousands of players simultaneously while other video games can play only with a few people and the internet is not neccesary.

2. Would there be stresses in living in a virtual world?

There would be no serious stresses in living in the virtual world because the failure could be not disasterous.

3. Look at e-bay and see what is being sold from secondlife and other on-line game forum. Is the economy from these games real?

The economy from online games is real, people sell the virtual items in the games by using money in the real world. For example, they sell the virtual houses in secondlife.

title: User:Naruemol.p


text:
User:5180402jiraporn

Homework 4 1. MMOGs is capable of supporting hundreds or thousands of players simultaneously, but in the video game, it is not supporting that many people. 2. It might be when you just got in there because you don't know any people and you don't know how to do it. Moreover, you aren't familiar with the atmosphere and places. 3. For the second life, there are bundle,and land. For other on-line games, there are CDs, and strategy guide.--5180402jiraporn 15:19, 23 January 2010 (UTC)5180402 Jiraporn

Homework 5 Manufacturer :		Windows TruefasterV Edition Mainboard :		Gigabyte GA-MA770-DS3P Chipset :		AMD RD770 Processor :		AMD Phenom X3 8450 @ 2100 MHz Physical Memory :	2048 MB (2 x 1024 DDR2-SDRAM ) Video Card :		ATI Radeon HD 4670 Hard Disk :		WDC (320 GB) DVD-Rom Drive :	ATAPI DVD A DH20A4P DVD-Rom Drive :	LMXWX LEVOPY3OL SCSI CdRom Device Monitor Type :	LG Electronics W1942 - 19 inches Network Card :	Realtek Semiconductor RTL8168/8111 PCI-E Gigabit Ethernet NIC Operating System :	Microsoft Windows XP Professional 5.01.2600 Service Pack 2 DirectX :		Version 9.0c (¡Ñ¹ÂÒÂ¹ 2009) --5180402jiraporn 05:49, 5 February 2010 (UTC)5180402 Jiraporn

1.How do you open the Select Pane in PowerPoint 2007? Home, edititng, select,selection pane. 2.In PowerPoint 2007, how do you change the maximum number of Undoes to 30? 3.How do you save a PowerPoint 2007 file as a web page? Office button, save as, save as type, choose web page, click save. 4.How do you change the color of a SmartArt object in PowerPoint 2007? Insert, illustrations, smartart, choose one, right click on it, format shape, color. 5.In PowerPoint 2007, how do you include slide numbers on every slide? Insert, text, slide number, choose slide number, apply to all. 6.How do you change the slide orientation of a PowerPoint 2007 presentation to portrait? Design, page setup, slide orientation, choose portrait. 7.How do you modify a textbox so that its text shrinks to fill the space in the shape in PowerPoint 2007? Right click on the text box, format text effects, resize spae to fit text. 8.How do you add a circle shape to a slide in PowerPoint 2007? Go to Insert, illustrations, shapes, click on circle shape, drag how big do you want on the page. 9.On the Ribbon in PowerPoint 2007, how do you change text in the textbox to WordArt? Go to Insert, Text, click WordArt, choose the one that you like, Type the word in the text box. 10.How do you open a current presentation in PowerPoint 2007? Go to Slide, start slide show, from curret slide. 11.How do you turn on the grids in PowerPoint 2007? Right click, grid and guides, displays grid on screen, ok. 12.What will allow you to quickly make a PowerPoint presentation as quickly as you can type?

13.How do you go to Handout Master in PowerPoint 2007#What does the Contrast function do in PowerPoint 2007? View, presentation views. 14.In PowerPoint 2007, how do you print out the slide you are currently looking at? Go to Offic Button, choose Print, and click on Print, choose slides and type the page number, and click OK.--5180402jiraporn 06:18, 12 February 2010 (UTC)5180402 Jirapron

license: Creative Commons - Attribution Share-Alike - https://creativecommons.org/licenses/by-sa/4.0/

title: User:5180402jiraporn


text:
User:IC5080669

IN Class Active Quiz 12022010
1. How do you open the Select Pane in PowerPoint 2007? -- Home/ editing/ select/ selection pane.

1.In PowerPoint 2007, how do you change the maximum number of Undoes to 30? --

1. How do you save a PowerPoint 2007 file as a web page? -- Office button, go to Save as/save as type/ and choose webpage

1. How do you change the color of a SmartArt object in PowerPoint 2007? -- Insert/ Illustration/ SmartArt/ List/ choose one/ then right click on it/ choose on Format Shape/ fill/ Color.

1. In PowerPoint 2007, how do you include slide numbers on every slide? -- Insert/ Text/ Slide number/ Include on slide/ Slide number/ apply.

2. How do you change the slide orientation of a PowerPoint 2007 presentation to portrait? -- Design/ Page setup/ slide orientation/ choose portrait.

3. How do you modify a textbox so that its text shrinks to fill the space in the shape in PowerPoint 2007? -- Insert/ Textbox/ Right click on textbox/ size and position/ then change to size as you want. -- Right click on textbox/ format shape/ textbox/ autofit/ resize shape to fit text. 4. How do you add a circle shape to a slide in PowerPoint 2007? -- Insert/ illustration/ shapes/ basic shapes/ click on a circle shape then put on your slide.

5. On the Ribbon in PowerPoint 2007, how do you change text in the textbox to WordArt? -- Go to insert/ text/ WordArt/ Choose the one that you like/ type words on Your Text Here.

6. How do you open a current presentation in PowerPoint 2007? -- Go to Slide show/ Start slide show/ From current slide.

7. How do you turn on the grids in PowerPoint 2007? -- Right-click/ Grid and Guides/ Grid setting/ check on display grid on screen.

8. What will allow you to quickly make a PowerPoint presentation as quickly as you can type? --

9. How do you go to Handout Master in PowerPoint 2007#What does the Contrast function do in PowerPoint 2007? -- view/ presentation view

10. In PowerPoint 2007, how do you print out the slide you are currently looking at? -- Office botton/ Print/ Print range/ Slides and put the number of page that you want to print.

Homework 4
1.What are MMOGs and how do they differer from regular video games?

The difference between MMOGs and the regular video games is that the large capacity of numbers who play in the game. MMOGs is a massively multiplayer online game which contianed a large number of people all over the world, and they can play game via the internet so they can contact with other people more easily. On the other hand, regular video game can play with just a fews people and locally so they may not able to connect with other people in different places, or in different countries. Moreover, players in the secondlife can explore and meet other players in the game which similar to real life by using avatars to represent themself, they will have their own socialize, or participate in individual group and do the activites, so that they can crate and trade products and services with other players.

2. Would there be stresses in living in a virtual world?

In my opinion, for the players who don't play game in virtual world seriously, they would have no stresses when they are playing the a virtual world because they will have nothing to lose for real in the game. All players will use the fake name and differen types of avatars to represent themselves in the game so if they just take no serious, they won't lose or get anything. However, there still are some players that play this game for their business, which this types of players might be so stressful when they are living in a virtual world because the business in the game could help them to have a big value of items that they trade in the real world.

3. Look at e-bay and see what is being sold from secondlife and other on-line game forum. Is the economy from these games real?

On e-bay, people are selling their money in the game by using real money in the real world. Also, there are some players that selling clothes or outfits of avatars in the game. While, other online game rarely selling things in real life from the game. In my opinion, the economy form these games are real, as I can see from the ebay and other sources, there are many people sell their money and items in the game, and they could make good profits in real life.

title: User:IC5080669


text:
User:T t0n9

Homework 4

1. It is use to connect to people through out the world.

2. No The charcter inside the game is not you, it is what you want to be.

3. Yes

--T t0n9 16:13, 23 January 2010 (UTC)

--- Each student answer the questions on his or her wikiversity User page:

1.How do you open the Select Pane in PowerPoint 2007? You can open it by click at the text box and then click at format then go to arrange and click at selection pane.

2.In PowerPoint 2007, how do you change the maximum number of Undoes to 30? click at office buttern then click at power point option then adavanced then changed the undoes number to 30.

3.How do you save a PowerPoint 2007 file as a web page? office buttern then save as then select at save as type the choose it to save as web page.

4.How do you change the color of a SmartArt object in PowerPoint 2007? insert > smart art > select one of them > design > smart art style > changes colours.

5.In PowerPoint 2007, how do you include slide numbers on every slide? Insert > text > slide number > tick at slide number.

6.How do you change the slide orientation of a PowerPoint 2007 presentation to portrait? Design > page setup > slide orentation > portrait

7.How do you modify a textbox so that its text shrinks to fill the space in the shape in PowerPoint 2007? Right click at shape > format shape > text box > tick at shrinks to fill the space.

8.How do you add a circle shape to a slide in PowerPoint 2007? Insert >illustrations > shape > circle.

9.On the Ribbon in PowerPoint 2007, how do you change text in the textbox to WordArt? insert > text > word art > highlight at the text > type your text.

10.How do you open a current presentation in PowerPoint 2007? F5

11.How do you turn on the grids in PowerPoint 2007? view > show/hide > grids line

12.What will allow you to quickly make a PowerPoint presentation as quickly as you can type? click at outline

13.How do you go to Handout Master in PowerPoint 2007#What does the Contrast function do in PowerPoint 2007? view > presentation view > handout master # make the colour of the picture to be more white or more black.

14.In PowerPoint 2007, how do you print out the slide you are currently looking at? office button > print > select at current slide. --T t0n9 08:30, 12 February 2010 (UTC)

title: User:T t0n9


text:
User:Pajaree/homework4

1.What are MMOGs and how do they differer from regular video games?

MMOGs are played on the internet with the large number of people who are members of a particular game, and in one server can be up to a few thousands people. Moreover, in the game world, players are able to interact with each while they are online. On the other hand, regular video games can be only one to four people at the time, and the internet connection is not needed. 2. Would there be stresses in living in a virtual world?

There should not be serious stresses in a virtual world because everything that players either gain or lose in virtual world has no effects in their real lives. However, there might be some players who actually believe that consequences in a game would also be outcomes in their everyday lives. In this case, those players could get crucially stressed in a virtual world.

3. Look at e-bay and see what is being sold from secondlife and other on-line game forum. Is the economy from these games real?

On e-bay, there are items that basiclly helping players to win a particular game. Besides,the economy from the games is real as we can see they sell things on e-bay and other places so that the game companies can make money out of it.

title: User:Pajaree/homework4


text: File:HW1-Q6 Plot2.jpg

title: File:HW1-Q6 Plot2.jpg


text: User talk:Egm6341.s10.team3.heejun

title: User talk:Egm6341.s10.team3.heejun


text: File:HW 2 4.pdf

title: File:HW 2 4.pdf


text: File:HW 2 4 1.png

title: File:HW 2 4 1.png


text: File:HW 2 4 2.png

title: File:HW 2 4 2.png


text:
User:Egm6341.s10.Team4.roni/HW2

HW2

Prob 4 - [[media:HW_2_4.pdf|PDF file]] [[media:HW_2_4_1.png|Page1]] [[media:HW_2_4_2.png|Page2]]

Prob 9 - [[media:HW_2_9_1.pdf|PDF file]] [[media:HW_2_9_1.png|Page1]]

Prob 16- [[media:HW_2_16.pdf|PDF file ]] [[media:HW_2_16_1.png|Page1 ]] [[media:HW_2_16_2.png|Page2]] [[media:HW_2_16_3.png|Page3]] [[media:Int_Table.png|a) Int result ]] [[media:Int.jpg|c) no convergance I(n)]] [[media:W_Table.png|d1) W table]] [[media:li8.png|d2) li functions n =8]]

title: User:Egm6341.s10.Team4.roni/HW2


text:
User:Egm6341.s10.team2.lee

Hello. This my Numerical Methods for Engineering Analysis-I (EGM 6341) page. Thanks for visiting. Egm6341.s10.team2.lee 21:12, 27 January 2010 (UTC)

title: User:Egm6341.s10.team2.lee


text: User:Supertouch

title: User:Supertouch


text:
User:Techexplo/In-class Work

= In-Class Homework = Homework will be assigned during class. Sometimes it will be complete during that time period, but sometimes you'll need extra time to finish it.

Most of this homework, I'll want posted to your wikiversity site. To make group work easier, sometimes I'll have the group post the final product here, but I also want you to at least post a link pointing to your homwork on your wikiversity site.

Student Links for Term 1, 2011

 * Anand
 * Apawan
 * Charyanaan
 * Methinee
 * Nannapad
 * Piyanut
 * Supasin
 * Usanee

Archived Homework
/Class Term 1, 2010/

title: User:Techexplo/In-class Work


text:
User talk:Techexplo/In-class Work/January 24, 2010

Good job with this homework. I want the class to further refine the list and list at explore the topics. For Jan. 31, 2010. I want you three to agree on what technology you'd like to do the project on. It should be something can be commercialized and can also help an organization internally as well.--Techexplo 03:15, 24 January 2010 (UTC)


text:
User:GreatmanKing

GreatmanKing
Jason Smith, (born September 28, 1987) is a presently unemployed and somewhat disturbed 22 year old living in a basement apartment and altogether not doing very much at the present point in time. I'm here to complete a couple of Courses here at the Wikiversity and meet some new and interesting people.

title: User:GreatmanKing


text:
University of Florida/Egm6341/s10.team3.aks

(10) Prove Simple trapezoidal rule
Ref. Lecture notes p.8-2]

Problem Statement
Use (2) in Slide 8-2] to obtain Simple trapezoidal rule.

Solution
Given

$$I_1 =\Big[\int_a^b l_{\text{o}} (x)dx\Big] f(x_{\text{o}})$$ + $$\Big[\int_a^b l_1 (x)dx\Big] f(x_1)$$

where

$$l_{\text{o}}(x) = \frac{x - x_1} {(x_{\text{o}} - x_1)}$$,

$$l_1 (x) = \frac {x - x_{\text{o}}} {(x_1 - x_{\text{o}}}$$,

$$ x_{\text{o}} = a $$

$$ x_1 = b $$

Now $$  I_1 = \Big[\int_a^b \frac{x - x_1} {x_{\text{o}} - x_1} dx\Big] f(x_{\text{o}})$$ + $$\Big[\int_a^b \frac{x - x_{\text{o}}} {x_1 - x_{\text{o}}} dx\Big]  f(x_1)$$

= $$[\frac{x^2 /2 - bx} {a - b}]_a^b  f(a) + [\frac{x^2 /2 - ax} {b - a}]_a^b  f(b)$$

= $$[(\frac{(\frac{b^2}{2} - b^2)- (\frac{a^2} {2} - ab))} {(a - b)}] f(a) + [\frac{(\frac{b^2}{2} - ab)- (a^2 /2 - a^2)} {(b - a)}] f(b)$$

= $$[\frac{(b-a)^2}{2(b - a)}] f(a)+ [(\frac{(b-a)^2}{2(b - a)}] f(b)$$

= $$[\frac{(b-a)}{2}] (f(a) + f(b))$$

which is same as equation (1) Slide p.7-1

This completes the Proof of trapezoidal rule

(11) Expansion of Lagrange functions
Ref: Lecture notes p.8-3 [media:Egm6341.s10.mtg8.pdf|

Problem Statement
Expand(4) from Slide (8-3 [media:Egm6341.s10.mtg8.pdf]]) to obtain $$P_2 (x_j)= \sum_{i=0}^2 l_i(x_j) f(x_i) = f(x_j)$$

Solution
$$P_2 (x_j)= \sum_{i=0}^2 l_i(x_j) f(x_i)= l_{\text{o}}(x_j)f(x_{\text{o}})+ l_1(x_j)f(x_1)+ l_2 (x_j)f(x_2)$$

where  $$ j = 0 ,1 ,2 $$

but when $$ i=j $$ $$ l_i(x_j) = 1 $$

and when i$$ \ne  $$j $$ l_i(x_j) = 0 $$

then only surviving terms are given by

$$\displaystyle P_2 (x_j)= l_{\text{o}}(x_{\text{o}}) f(x_{\text{o}}) + l_1 (x_1)  f(x_1)+ l_2 (x_2)  f(x_2) = f(x_{\text{o}}) + f(x_1) + f(x_2)=f (x_j) $$

(3) Plot Functions Sin (x),-cos (x)and Sin(x)+cos(x)
Ref. Lecture notes p.3-3 [media:Egm6341.s10.mtg3.pdf|

Problem Statement
Plot f(x)= sin(x) and g(x) = - cos(x) in the interval of [0,pi]]

and also find $$||f(x)||\infin, ||g(x)||\infin and ||f(x)-g(x)||\infin$$

Solution
Plot f(x)= sin(x) in interval [0,pi]

Matlab code :

Plot :

f(x)=y= Sin(x)

Plot g(x)= - cos(x) in interval [0,pi]

Matlab code :

Plot :

g(x)= y = - cos(x)

Plot f(x)-g(x)= Sin(x)+cos(x)

Matlab code :

$$||f(x)||\infin = 1$$

$$||g(x)||\infin = 1$$

$$||f(x)-g(x)||\infin = \sqrt{2}$$

Abhishekksingh 16:25, 27 January 2010 (UTC)


text:
User talk:Ehsankakaei

 Hello Ehsankakaei, and welcome to Wikiversity! If you need help, feel free to visit my talk page, or contact us and ask questions. After you leave a comment on a talk page, remember to sign and date; it helps everyone follow the threads of the discussion. The signature icon in the edit window makes it simple. To get started, you may

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Feel free to leave a message on my talk page if you have any questions or need help. --mikeu talk 08:18, 24 January 2010 (UTC)

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text:
User talk:MatthewH~enwikiversity

 Hello MatthewH, and welcome to Wikiversity! If you need help, feel free to visit my talk page, or contact us and ask questions. After you leave a comment on a talk page, remember to sign and date; it helps everyone follow the threads of the discussion. The signature icon in the edit window makes it simple. To get started, you may

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Feel free to leave a message on my talk page if you have any questions or need help. --mikeu talk 08:18, 24 January 2010 (UTC)

Your account will be renamed
Hello,

The developer team at Wikimedia is making some changes to how accounts work, as part of our on-going efforts to provide new and better tools for our users like cross-wiki notifications. These changes will mean you have the same account name everywhere. This will let us give you new features that will help you edit and discuss better, and allow more flexible user permissions for tools. One of the side-effects of this is that user accounts will now have to be unique across all 900 Wikimedia wikis. See the announcement for more information.

Unfortunately, your account clashes with another account also called MatthewH. To make sure that both of you can use all Wikimedia projects in future, we have reserved the name MatthewH~enwikiversity that only you will have. If you like it, you don't have to do anything. If you do not like it, you can pick out a different name.

Your account will still work as before, and you will be credited for all your edits made so far, but you will have to use the new account name when you log in.

Sorry for the inconvenience.

Yours, Keegan Peterzell Community Liaison, Wikimedia Foundation 23:43, 17 March 2015 (UTC)

Renamed
 This account has been renamed as part of single-user login finalisation. If you own this account you can |log in using your previous username and password for more information. If you do not like this account's new name, you can choose your own using this form after logging in: . -- Keegan (WMF) (talk) 06:15, 19 April 2015 (UTC)

title: User talk:MatthewH~enwikiversity


text:
User talk:Prithpal singh anand

 Hello Prithpal singh anand, and welcome to Wikiversity! If you need help, feel free to visit my talk page, or contact us and ask questions. After you leave a comment on a talk page, remember to sign and date; it helps everyone follow the threads of the discussion. The signature icon in the edit window makes it simple. To get started, you may

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Feel free to leave a message on my talk page if you have any questions or need help. --mikeu talk 08:18, 24 January 2010 (UTC)

title: User talk:Prithpal singh anand


text:
User talk:Korakoch

 Hello Korakoch, and welcome to Wikiversity! If you need help, feel free to visit my talk page, or contact us and ask questions. After you leave a comment on a talk page, remember to sign and date; it helps everyone follow the threads of the discussion. The signature icon in the edit window makes it simple. To get started, you may

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Feel free to leave a message on my talk page if you have any questions or need help. --mikeu talk 08:19, 24 January 2010 (UTC)

title: User talk:Korakoch


text:
User talk:Abhishekksingh

 Hello Abhishekksingh, and welcome to Wikiversity! If you need help, feel free to visit my talk page, or contact us and ask questions. After you leave a comment on a talk page, remember to sign and date; it helps everyone follow the threads of the discussion. The signature icon in the edit window makes it simple. To get started, you may

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And don't forget to explore Wikiversity with the links to your left. Be bold to contribute and to experiment with the sandbox or your userpage, and see you around Wikiversity! If you're a twitter user, please follow http://twitter.com/Wikiversity. --Mu301Bot 08:19, 24 January 2010 (UTC)

Feel free to leave a message on my talk page if you have any questions or need help. --mikeu talk 08:19, 24 January 2010 (UTC)

Copyright problem with Image:Composite Tapazoidal rule.png

 * Can you confirm that you were the creator of that file? If so it can be restored from the wiki-dustbin (and then renamed properly :).  –SJ + > 00:24, 7 April 2010 (UTC)

title: User talk:Abhishekksingh


text:
User talk:Zollerriia

 Hello Zollerriia, and welcome to Wikiversity! If you need help, feel free to visit my talk page, or contact us and ask questions. After you leave a comment on a talk page, remember to sign and date; it helps everyone follow the threads of the discussion. The signature icon in the edit window makes it simple. To get started, you may

 * Take a guided tour and learn to edit.
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 * Read an introduction for teachers and find out how to write an educational resource for Wikiversity.
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 * Chat with other Wikiversitans on #wikiversity-en.

And don't forget to explore Wikiversity with the links to your left. Be bold to contribute and to experiment with the sandbox or your userpage, and see you around Wikiversity! If you're a twitter user, please follow http://twitter.com/Wikiversity. -- Pmlineditor  ∞  09:17, 24 January 2010 (UTC) -- Pmlineditor  ∞  09:17, 24 January 2010 (UTC)

title: User talk:Zollerriia


text:
User talk:Jade Knight/Archives/2009

Coming out from under the rock
Thanks for your long ago note -- I've signed up for the mentor program. I've been away from the wikis (for too long). Historybuff 07:08, 24 January 2009 (UTC)

WV:NOT
Hi Jade Knight. I hope I'm understanding you correctly in that your main objection to WV:NOT is the advocacy clause. Would you feel comfortable supporting the policy with that clause removed? See Wikiversity_talk:What_Wikiversity_is_not for details. --SB_Johnny talk 12:25, 13 February 2009 (UTC)

God'sGirl94
HEY!!!!!!!!! It's me from WIKIBOOKS!! How are ya? --God'sGirl94 13:45, 28 February 2009 (UTC)

French Mentoring / Parainage en français
Hello Jade Knight,

I just saw your message inviting me to mentor a French learning student, months after you posted it (and I feel sorry for that). I have to tell you that I might be able to mentor anyone for the moment: because of my studies, I have much work to do, and if I am still on holyday (and contributing to the French mirror) for the week being, I will soon have no more time to spare for any Wiki. --- Bonjour Jade Knight (enfin bonsoir pour moi),

je viens à peine de voir ton message m'invitant à parrainer un étudiant en français, alors que tu l'avais envoyé depuis plusieurs mois (et j'en suis désolée). Je dois t'informer que je ne pourrais sûrement parrainer personne pour l'instant : à cause de mes études, j'ai énormément de travail, et si je suis encore en vacances (ce qui me permet de contribuer sur les serveurs francophones) cette semaine, je n'aurai bientôt plus de temps pour participer à aucune Wiki.

--Klymene 02:43, 6 March 2009 (UTC)

Mentors
Hi! I saw that you've made some edits to the Mentors page a while back. I've been working on bringing the Mentorship program up to the next level. I'm hoping to model it, to a certain extent, on the Learning4Content program over at WikiEducator. I would appreciate your feedback. --AFriedman 17:31, 6 March 2009 (UTC)

Project Incubator
Please check Project_incubator for an update on HHF. I'd really appreciate someone's help over here. I have managed to gather some volunteers from my hostel who'd participate in discussion on the HHF/Highschool Help Forum, but I need the project to be set up well for that. Thanks again! --Dharav talk 12:03, 24 August 2009 (UTC)

French Mentoring
Salut— As of right now, I could probably comfortably take two more students, three if they're all beginning level. Eleraama 19:20, 28 August 2009 (UTC)

Universitas
No I am not a Classicist, my background was Physics. However if you start digging deep enough you always will invariably end up at the same place. I quite agree with you, everything today is about money, even science, even the search for truth that inspired those who came before us. But there are some signs that are promising. I for one am quite impressed by the "Free Software Movement" (Eben Moglen for example) As Eben Moglen points out this is not free like in free beer but free as it belongs to the Common ( with capital letter)  and from there, it seems to me is but a very small step to the Common Good  the principle Socrates for example was searching for. I think this concept Should be expanded into other/ all areas of human activities. Periodically attempts in this direction are made, but they seem to drown and are not heard of again. This however seems to me no excuse not to try. Wikiversity attracted me as a possible platform to start again such a thing -- make knowledge, experiences, and insights etc practical in the spirit of " Search for the Greater Good " otherwise it is just more free beer. For this reason I am in the process of starting the project: " Designing for the Commons" here on wikiversity I am inexperienced in Computer "Things" thats one reason why it might be slow in getting going but again that is no excuse. In order to attract folks the quality has to be high, in other words it has to be valuable, it cannot be " Underwater Basket weaving" -- nobody gives a dam about..-- I worked in fluid dynamics and came up with the process of Dynamic Containment which I plan to use as a start. ( The picture / movie strips are just a start, no explanations yet, but it is coming be patient) The idea is to use technologies like this to develop actual useful applications collaboratively and free, that can stand up in the market place. I am convinced it can be done. I am also convinced if such practical attempts are anchored in what one might refer to as our Common humanistic inheritance it might influence enough folks so this thing we try to do will develop momentum on its own. I have no illusions that this will be easy or might even be successful, but that should not matter. Lewis Mumford expressed this more eloquently than I can Its taken from his book " The Condition of Man": ( These words accompany by a picture  " Dawn at  Lake George" by Alfred Stieglitz) "......the foreground is dark, and it will become darker before the day breaks. The purging of long accumulated poisons, the healing of ugly wounds, will not be done in a day:  all this needs time,patience, resolute effort, and a willingness to forgo selfish local gains for the sake of a larger common good -- the unification of mankind and the replenishment of life. Nothing that is worth doing in our time will be done easily; that is, without a spiritual rebirth.  Unless the blind recover their sight and the crippled learn to walk our very knowledge will slay us. No peace without struggle; no security without risk; no wholeness without simplification; no goods without measure; no love without sacrifice; no full life without the willingness to accept and transcend death in the very process of living. Those who have learned this lesson may build the City of Man." Altera vista 09:05, 2 September 2009 (UTC)

Hi JadeKnight!
Sorry I was out of contact for so long. Just got the computer set up. When are you free again?

Princeof500 07:57, 2 April 2009 (UTC)

I'm not on Wikiversity much either. But i do happen to have an MSN account, it is princetkmk@yahoo.com but I don't really go on that either. 203.219.84.197 04:40, 19 September 2009 (UTC)

Re:Wikinews DR
I happened to notice your open Dispute Resolution comment on Wikinews, so I replied to you there. Sorry that took so long, it's just that the need for DR rarely comes up on Wikinews, so we tend not to check that page very often:P. Gopher65talk 01:29, 24 January 2009 (UTC)
 * I understand your point of view, and that is something that we are working on. I have a couple points:

 * 1) We can't publish substandard articles due to the fact that we are now listed on Googlenews. If our quality drops below a certain point, we'll get booted off. This means that when an article doesn't meet our pre-set criteria, it will have its publication delayed until it is fixed. Unfortunately the amount of time that it takes to fix an article is sometimes great enough that an article can no longer be published. This is unavoidable. That's just how news is.

 * 2) As I stated before, news is by definition new. It can't be old. Wikinews is in direct competition with major news outlets, so we have to get our news out as quickly as possible. An article might takes months to write on Wikipedia, going through major rewrites and copyediting cycles; all of that needs to be done in HOURS on Wikinews. So, yes, it is a more stressful, less friendly environment to write an article in, but that has nothing to do with the people on Wikinews. That's just the way news is. If you'd ever been in a commercial newsroom you'd understand just how laid back we at Wikinews are;). There is constant pressure to get the story out ASAP. Again, that's just the nature of news; it can't be any different. Gopher65talk 22:24, 4 February 2009 (UTC)

 * Sorry for bugging you, but I just thought of a point of confusion that you might have. There are 2 types of articles on Wikinews: rewritten articles and Original Reporting. Rewritten articles are when you take an existing story that was run by several competing news agencies and rewrite it in your own words. These stories can be no more than 3 days old. However, with Original Reporting there is no time limit. If you go out and do real research for a story, interview, etc, there is no time limit on how long it can be in development. Sometimes such articles spend weeks or months being researched and written. Gopher65talk 14:53, 11 February 2009 (UTC)

 * Yes, that point was mentioned in the last comment by one of the admins who commented on your DR request. He commented that people were rather rude and unhelpful in the Deletion Request. Personally, I suspect that much of that rudeness comes from the fact that most of the core Wikinews community (the kind of people who vote on Deletion Requests) has been around for a while, and they all know all the rules. They mostly deal with each other, and (with occasional exceptions), their rudeness is tongue-in-cheek. They also seem to assume that any new person who writes an article will have read all the help pages, and will know what to do. Clearly this doesn't happen, and they should adapt their actions to suit the situation. Some of us are trying to change this attitude. Time will tell if we'll succeed.

 * As to your criticism about our policies not existing, I will note that these policies *do* exist in writing, and they lay out EXACTLY what is allowed and what isn't. They are easily accessible from either the sidebar or the welcome message for anyone who wants to read them. Unfortunately most of the people who come to Wikinews come from Wikipedia, and they assume that because they know the rules of Wikipedia, they will be fine on Wikinews. They assume that this means that they don't need to read the help pages, and can just jump right into editing. Wikinews has darned near opposite rules to those on Wikipedia (except for obvious things like vandalism), so following Wikipedia rules on Wikinews is a good way to not get published.

 * Anyway, while I respect your decision not to edit Wikinews anymore, most of your issues are either being addressed, or never existed in the first place. Gopher65talk 02:46, 17 February 2009 (UTC)

 * It is stated in the Content Guide, which is linked to from the Welcome Template, which all new users (should) get on their talk pages. Gopher65talk 15:10, 1 March 2009 (UTC)

I've decided that I'm going to create a "policies in a nutshell" page, which will essentially be a bulleted list of all our critical policies. I'll see if I can get it listed on the left-hand side toolbar, as well as in the welcome template. That should make it easier for new users to find key policies, but it won't help people who choose not to read the policies in the first place.

I'm also going to try and push for a "Welcome-bot" that will automatically post the welcome template on the talk pages of new users in order to ensure that they have easy access to the detailed list of policies, should they desire it. Currently the welcome template gets posted on the pages of users who manually create accounts, and on the pages of people who chose to edit, but it doesn't get placed on the accounts that are auto-created by the Global Accounts system. Gopher65talk 15:59, 1 March 2009 (UTC)

 * Annnnnnnd, Wikinews FINALLY has that welcome-bot up and running smoothly. Well, welcome-extension now, which is better than a bot. The "policies in a nutshell" page idea was replaced with further revamps to the welcome template, which links to all critical policy-in-a-nutshell pages. Hopefully this will help prevent bad experiences like yours from recurring:). That took a while, huh? We move almost as fast as the speed of committee over there, heh (though not because of bureaucracy (unlike wikipedia) so much as because we have a very small userbase and a very long to-do list). Gopher65talk 01:10, 27 February 2010 (UTC)

Mentoring
Hi,

Sorry for the long answer time, I have been very busy lately. I am afraid I won't be able to monitor people this year, because I am working on a double degree, thus I have a lot of work. I think I will unsubscribe as a mentor for this year, but I hope I will have time later for this. Xzapro4 19:49, 18 October 2009 (UTC)

Hi,

I would be comfortable with one or two students to begin with. However, I won't be able to chat using audio. Text chatting using googleTalk and e-mail will be ok. As for the level of the students, I think I would be better with non-beginner students, I'm not sure I would be proficient in teaching from scratch.

I also talk almost fluently Spanish, so if some students are from a spanish-speaking country, I can teach in Spanish.

Keep me posted. Albane69 17:34, 29 March 2010 (UTC)

title: User talk:Jade Knight/Archives/2009


text:
User:Egm6341.s10.Team4.andy/HW1

= Problem 1: Limits=

Given
Refer Lecture slide 2-1 for problem statement

 * {| style="width:70%" border="0" align="center"

f(x) = \frac{e^x - 1}{x} $$ $$
 * $$\displaystyle
 * $$\displaystyle \longrightarrow (1)

 * }.
 * }.

Find
1. Find

 * {| style="width:70%" border="0" align="center"

\lim_{x \rightarrow 0}f(x) $$
 * $$\displaystyle

 * }.
 * }.

2. Plot
 * {| style="width:70%" border="0" align="center"

f(x),\ x\in[0,1] $$
 * $$\displaystyle

 * }.
 * }.

Solution
1. Limit

The Taylor series expansion for $$\displaystyle e^x $$ is given by,

 * {| style="width:70%" border="0" align="center"

\begin{align} e^x &= \sum_{i=0}^n \frac{x^i}{i!} \\ &= 1 + \sum_{i=1}^n \frac{x^i}{i!} \end{align} $$
 * $$\displaystyle

 * }.
 * }.

Dividing throughout by x,

 * {| style="width:70%" border="0" align="center"

 * $$\displaystyle

\Rightarrow \frac{e^x - 1}{x} = \sum_{i=1}^n \frac{x^{i-1}}{i!}

$$

 * }.
 * }.

which is equal to $$\displaystyle f(x)$$ in Equation(1).

 * {| style="width:70%" border="0" align="center"

\begin{align} \Rightarrow f(x) &= \frac{e^x - 1}{x} \\ &= \sum_{i=1}^n \frac{x^{i-1}}{i!} &= \frac{x^0}{1!} + \frac{x^1}{2!} + \frac{x^2}{3!} + \cdots \end{align} $$
 * $$\displaystyle

 * }.
 * }.

Applying limits on both sides,

 * {| style="width:70%" border="0" align="center"

 * $$\displaystyle

\Rightarrow \lim_{x \rightarrow 0}f(x) = \frac{0^0}{1!} + \cancelto{0}{\frac{0^1}{2!}} + \cancelto{0}{\frac{0^2}{3!}} + \cdots

$$

 * }.
 * }.

Hence,

 * {| style="width:70%" border="0" align="center"

$$\displaystyle \Rightarrow \lim_{x \rightarrow 0}f(x) = 1 $$ $$
 * style="width:20%; padding:10px; border:2px solid #8888aa" |
 * style="width:20%; padding:10px; border:2px solid #8888aa" |
 * $$\displaystyle \longrightarrow (2)

 * style= |

 * }.
 * }.

2. Plot convergence of $$\displaystyle f(x) $$ .

To visualize the limit as in Equation (2), $$\displaystyle f(x) \to 1 \ as\ x \to 0 $$, two plots are provided below one with $$\displaystyle n = 10 $$ in the Taylor series, & with 10 points on x-axis scale, and another with $$\displaystyle n = 100 $$, & with 100 points on x-axis scale.

Matlab Code:

Plots:

.

= Problem 2: Taylor Series Terms =

Given
Refer Lecture slide 2-3 for problem statement.

From lecture slide 2-2, for a continuous function $$\displaystyle f(x) $$, the Taylor series is given by

 * {| style="width:100%" border="0" align="left"

f(x)= p_n(x) + R_{n+1}(x) $$
 * $$\displaystyle
 * $$\displaystyle
 * }.
 * }.

such that $$\displaystyle f^{n+1}(x) $$ exists and continuous,

 * {| style="width:100%" border="0" align="left"

f^{n+1}(x) := \frac{d^{n+1}}{dx^{n+1}} f(x) $$
 * $$\displaystyle
 * $$\displaystyle
 * }.
 * }.

where,

 * {| style="width:100%" border="0" align="left"

p_n(x):= f(x_0) + \frac{(x-x_0)}{1!} f^1(x_0) + \cdots + \frac{(x-x_0)^n}{n!} f^n(x_0) $$ $$
 * $$\displaystyle
 * $$\displaystyle
 * $$\displaystyle \longrightarrow (1)
 * }.
 * }.

and,

 * {| style="width:100%" border="0" align="left"

R_{n+1}(x):= \frac{1}{n!} \int_{x_0}^{x}(x-t)^nf^{n+1}(t)dt $$ $$
 * $$\displaystyle
 * $$\displaystyle
 * $$\displaystyle \longrightarrow (2)
 * }.
 * }.

Find
To find $$\displaystyle p_n(x) $$ and $$\displaystyle R_{n+1}(x) $$ for $$\displaystyle e^x $$.

Solution
Taking $$\displaystyle x_0 = 0 $$, Equation (1) for $$\displaystyle f(x) = e^x $$ becomes,

 * {| style="width:100%" border="0" align="left"

p_n(x)= e^0 + \frac{(x-0)}{1!} e^0 + \frac{(x-0)^2}{2!} e^0 + \cdots + \frac{(x-0)^n}{n!} e^0 $$
 * $$\displaystyle
 * $$\displaystyle
 * }.
 * }.

which is,

 * {| style="width:100%" border="0" align="left"

$$\displaystyle p_n(x)= 1 + x + \frac{x^2}{2!} + \frac{x^3}{3!} + \cdots + \frac{x^n}{n!} $$ $$
 * style="width:35%; padding:10px; border:2px solid #8888aa" |
 * style="width:35%; padding:10px; border:2px solid #8888aa" |
 * style= |
 * $$\displaystyle \longrightarrow (3)

 * }.
 * }.

From Lecture slide 2-3, Equation(2) is given by,

 * {| style="width:100%" border="0" align="left"

R_{n+1}(x)= \frac{(x-x_0)^{n+1}}{(n+1)!} f^{n+1}(\xi) $$ $$
 * $$\displaystyle
 * $$\displaystyle
 * $$\displaystyle \xi \in [x_0,x] $$
 * $$\displaystyle \longrightarrow (4)
 * }.
 * }.

For $$\displaystyle x_0 = 0 $$ and $$\displaystyle f(x) = e^x $$ Equation (4) becomes,

 * {| style="width:100%" border="0" align="left"

$$\displaystyle R_{n+1}(x)= \frac{x^{n+1}}{(n+1)!} e^\xi $$ $$
 * style="width:35%; padding:10px; border:2px solid #8888aa" |
 * style="width:35%; padding:10px; border:2px solid #8888aa" |
 * style = |
 * $$\displaystyle \longrightarrow (5)
 * }.
 * }.

= Problem 3: Infinity Norms =

Given
Refer Lecture slide 3-3 for problem statement.

 * {| style="width:100%" border="0" align="left"

f(x)= sin x $$ $$
 * $$\displaystyle
 * $$\displaystyle
 * $$\displaystyle \longrightarrow (1)
 * }.
 * }.

 * {| style="width:100%" border="0" align="left"

g(x)= sin (x-\frac{\pi}{2}) = -cos x $$ $$
 * $$\displaystyle
 * $$\displaystyle
 * $$\displaystyle \longrightarrow (2)
 * }.
 * }.

Find
1. Plot $$\displaystyle f(x), g(x) $$ given $$\displaystyle x \in [0,\pi] $$.

2. Find $$\displaystyle \parallel f \parallel_{\infty}, \parallel g \parallel_{\infty}, \parallel f - g\parallel_{\infty} $$

Solution
1.

Matlab Code:

Plot:

.

2.

The infinity norms are given as,

 * {| style="width:100%" border="0" align="left"

\parallel f \parallel_{\infty} = \underset{x}{max} |f| $$
 * $$\displaystyle
 * $$\displaystyle
 * }.
 * }.

or

 * {| style="width:100%" border="0" align="left"

\parallel f - g\parallel_{\infty} = \underset{x}{max} |f - g| $$
 * $$\displaystyle
 * $$\displaystyle
 * }.
 * }.

Min and Max Values from Matlab:

So, the infinity norms are given by,

 * {| style="width:100%" border="0" align="left"

$$\displaystyle \begin{align} \parallel f \parallel_{\infty} &= 1 \\ \parallel g \parallel_{\infty} &= 1 \\ \parallel f - g\parallel_{\infty} &= 1.414214 \end{align} $$
 * style="width:35%; padding:10px; border:2px solid #8888aa" |
 * style="width:35%; padding:10px; border:2px solid #8888aa" |
 * style = |

 * }.

= Problem 4: Integral Mean Value Theorem (IMVT)=

Given
From lecture slide [[media:Egm6341.s10.mtg2.pdf|2-4]], any function $$\displaystyle f(.) $$ continuous on $$\displaystyle [a,b] $$ with $$\displaystyle m = min(f(x)) $$ and $$\displaystyle M =  max(f(x)) $$,

 * {| style="width:70%" border="0" align="center"

m \le f(x) \le M $$ $$
 * $$\displaystyle
 * $$\displaystyle \longrightarrow (1)

 * }
 * }

Find
Lecture Slide [[media:Egm6341.s10.mtg5.pdf|5-1]]:

1. Prove IMVT for non-negative $$\displaystyle W(.) \Rightarrow W \ge 0$$, given by:

 * {| style="width:70%" border="0" align="center"

\int_{a}^{b}W(x)f(x)dx = f(\xi)\int_{a}^{b}W(x)dx $$ $$
 * $$\displaystyle
 * $$\displaystyle \longrightarrow (2)

 * }
 * }

where $$\displaystyle \xi \in [a,b] $$

2. Prove IMVT for non-zero $$\displaystyle W(.) \Rightarrow W \ne 0$$.

Solution
1. $$\displaystyle W(x) \ge 0$$ .

Equation (1),

 * {| style="width:70%" border="0" align="center"

m \le f(x) \le M $$
 * $$\displaystyle

 * }.
 * }.

Multiplying by non-negative $$\displaystyle W(x) $$,

 * {| style="width:70%" border="0" align="center"

\Rightarrow m W(x) \le W(x)f(x) \le M W(x) $$
 * $$\displaystyle

 * }.
 * }.

Integrating from a to b with respect to x,

 * {| style="width:70%" border="0" align="center"

\Rightarrow m \int_{a}^{b} W(x)dx \le \int_{a}^{b} W(x)f(x)dx \le M \int_{a}^{b} W(x)dx $$ $$
 * $$\displaystyle
 * $$\displaystyle \longrightarrow (3)

 * }.
 * }.

Let the integral $$\displaystyle I $$ be,

 * {| style="width:70%" border="0" align="center"

I:=\int_{a}^{b} W(x)dx $$ $$
 * $$\displaystyle
 * $$\displaystyle \longrightarrow (4)
 * }.
 * }.

For $$\displaystyle I = 0 $$, the non-strict inequality Equation (3) holds true. So, we will take the case when $$\displaystyle I > 0$$.

Dividing (4) throughout (3),

 * {| style="width:70%" border="0" align="center"

\Rightarrow m \le \frac{1}{I} \int_{a}^{b} W(x)f(x)dx \le M $$ $$
 * $$\displaystyle
 * $$\displaystyle \longrightarrow (5)

 * }.
 * }.

From Lecture slide [[media:Egm6341.s10.mtg3.pdf|3-4]], we know that for every value in the closed interval $$\displaystyle [a,b] $$ there exists at least a value [need not be unique] $$\displaystyle \xi \in [a,b] $$ such that $$\displaystyle \zeta = f(\xi) = \frac{1}{b-a} \int_{a}^{b} f(x)dx$$, specifically for a continuous function $$\displaystyle f(x) $$.

With the same argument, there exists at least a value $$\displaystyle \xi_1 \in [a,b] $$ such that for a continuous function $$\displaystyle f(x) $$,

 * {| style="width:70%" border="0" align="center"

\Rightarrow \zeta_1 = f(\xi_1) = \frac{1}{I} \int_{a}^{b} W(x)f(x)dx $$ $$
 * $$\displaystyle
 * $$\displaystyle \longrightarrow (6)

 * }.
 * }.

Hence,

 * {| style="width:70%" border="0" align="center"

\Rightarrow f(\xi_1) I = \int_{a}^{b} W(x)f(x)dx $$
 * $$\displaystyle

 * }.
 * }.

proving Equation (2) for a non-negative $$\displaystyle W(x) $$,

 * {| style="width:70%" border="0" align="center"

$$\displaystyle \Rightarrow f(\xi_1) \int_{a}^{b} W(x)dx = \int_{a}^{b} W(x)f(x)dx $$ $$
 * style="width:20%; padding:10px; border:2px solid #8888aa" |
 * $$\displaystyle \longrightarrow (7)
 * style= |

 * }.
 * }.

2. $$\displaystyle W(x) \ne 0$$ .

For the case when $$\displaystyle W(x) > 0$$ the above proof holds.

Next we deal the case when $$\displaystyle W(x) < 0$$.

Multiplying Equation(1) by $$\displaystyle -W(x)$$ (this makes $$\displaystyle W(x) > 0$$ in the below equations),

 * {| style="width:70%" border="0" align="center"

\Rightarrow -m W(x) \ge -W(x)f(x) \ge -M W(x) $$
 * $$\displaystyle

 * }.
 * }.

Integrating from a to b with respect to x gives,

 * {| style="width:70%" border="0" align="center"

\Rightarrow -m \int_{a}^{b} W(x)dx \ge -\int_{a}^{b} W(x)f(x)dx \ge -M \int_{a}^{b} W(x)dx $$ $$
 * $$\displaystyle
 *
$$\displaystyle \longrightarrow (8)

 * }.
 * }.

Multiplying Equation(8) throughout by -1, we get Equation (3). Right from there, we can prove IMVT following the same procedure as explained above.

= Problem 5: IMVT Appication Example =

Given
The Integral Mean Value Theorem (IMVT) is given by,

 * {| style="width:70%" border="0" align="center"

\int_{a}^{b}W(x)f(x)dx = f(\xi)\int_{a}^{b}W(x)dx $$ $$
 * $$\displaystyle
 *
$$\displaystyle \longrightarrow (1)

 * }
 * }

where $$\displaystyle \xi \in [a,b] $$

Find
Refer Lecture slide [[media:Egm6341.s10.mtg5.pdf|5-1]] for problem statement.

From Lecture slide [[media:Egm6341.s10.mtg2.pdf|2-2]] the Remainder $$\displaystyle R_{n+1}(x)$$ of the Taylor series is given by,

 * {| style="width:70%" border="0" align="center"

R_{n+1}(x) := \frac{1}{n!} \int_{x_0}^{x} (x-t)^n f^{n+1}(t)dt $$ $$
 * $$\displaystyle
 *
$$\displaystyle \longrightarrow (2)

 * }.
 * }.

where $$\displaystyle f^{n+1}(t) $$ is the $$\displaystyle (n+1)^{th} $$ derivative of $$\displaystyle f(t) $$.

Using IMVT show that,

 * {| style="width:70%" border="0" align="center"

R_{n+1}(x) = \frac{(x-x_0)^{n+1}}{(n+1)!} f^{n+1}(\xi) $$ $$
 * $$\displaystyle
 *
$$\displaystyle \longrightarrow (3)

 * }.
 * }.

where $$\displaystyle \xi \in [x_0,x] $$.

Solution
Equation (2) is given by,

 * {| style="width:70%" border="0" align="center"

R_{n+1}(x) := \frac{1}{n!} \int_{x_0}^{x} \underbrace{(x-t)^n}_{W(t)} \underbrace{f^{n+1}(t)}_{g(t)}dt $$ $$
 * $$\displaystyle
 *
$$\displaystyle \longrightarrow (3)

 * }.
 * }.

Now, using IMVT we can pull out $$\displaystyle g(t) $$ valued at $$\displaystyle \xi $$ resulting in,

 * {| style="width:70%" border="0" align="center"

\Rightarrow R_{n+1}(x) = g(\xi)\frac{1}{n!} \int_{x_0}^{x} \underbrace{(x-t)^n}_{W(t)} dt $$ $$
 * $$\displaystyle
 *
$$\displaystyle \longrightarrow (4)

 * }.
 * }.

The integrand $$\displaystyle W(t) = (x-t)^n $$ is integrated from $$\displaystyle x_0 $$ to $$\displaystyle x $$. So, $$\displaystyle t \in [x_0,x]$$, which means $$\displaystyle (x-t) \ge 0$$. $$\displaystyle \Rightarrow W(t) \ge 0 $$.

 * {| style="width:70%" border="0" align="center"

\begin{align}
 * $$\displaystyle

\Rightarrow \int_{x_0}^{x} W(t)dt & = \int_{x_0}^{x} {(x-t)^n} dt \\ & = -\frac{1}{n+1} \left [ (x-t)^{n+1}\right]_{x0}^{x} \\ & = -\frac{1}{n+1} \left [ \cancelto{0}{(x-x)^{n+1}} - (x-x_0)^{n+1} \right ] \\ & = -\frac{1}{n+1} \left [- (x-x_0)^{n+1} \right ] \end{align} $$

 * }.
 * }.

So,

 * {| style="width:70%" border="0" align="center"

 * $$\displaystyle

\Rightarrow \int_{x_0}^{x} W(t)dt = \frac{(x-x_0)^{n+1}}{n+1}

$$ $$
 *
$$\displaystyle \longrightarrow (5)

 * }.
 * }.

Substituting (5) in (4),

 * {| style="width:70%" border="0" align="center"

\begin{align} \Rightarrow R_{n+1}(x) &= g(\xi)\frac{1}{n!} \frac{(x-x_0)^{n+1}}{n+1} \\ &= g(\xi)\frac{(x-x_0)^{n+1}}{(n+1)!} \\ &= f^{n+1}(\xi)\frac{(x-x_0)^{n+1}}{(n+1)!} \end{align} $$
 * $$\displaystyle

 * }.
 * }.

Hence Equation(3) is proved,

 * {| style="width:70%" border="0" align="center"

$$\displaystyle
 * style="width:20%; padding:10px; border:2px solid #8888aa" |
 * style="width:20%; padding:10px; border:2px solid #8888aa" |

\Rightarrow R_{n+1}(x):= \frac{1}{n!} \int_{x_0}^{x} (x-t)^n f^{n+1}(t)dt = \frac{(x-x_0)^{n+1}}{(n+1)!} f^{n+1}(\xi)

$$ $$
 *
$$\displaystyle \longrightarrow (6)
 * style= |
 * }.
 * }.

title: User:Egm6341.s10.Team4.andy/HW1


text:
User:Sgangte

Real Name = S PAUMINTHANG GANGTE

title: User:Sgangte


text:
User:Goldenman~enwikiversity/Islamic economic

what are the main principles of islamic economic


text:
User:Egm6341.s10.team4.anandankala

= Home Work 1= Problem 1.4

Problem 1.8

Problem 1.11

=Home Work 2=

Problem 2.3

Problem 2.9

Problem 2.15

=Home Work 3=

Problem 3.3

=Home Work 4=

Problem 4.3

=Home Work 5=

Problem 5.3

Problem 5.9

=Home Work 6=

Problem 6.3

Problem 6.9

=Home Work 7=

Problem 7.3

Problem 7.9

Problem 7.15

title: User:Egm6341.s10.team4.anandankala


text:
User:Egm6341.s10.team3.Min/HW1-x

= Problem 4 : Proof Taylor series by IMVT =

Given
See IMVT in [[media:egm6341.s10.p2-3.png|Lecture p.2-3]]
 * {| style="width:100%" border="0" align="left"

$$ with $$ w(x)\geqslant 0 \quad \forall \ x \in [a,b] $$
 * $$\displaystyle \int_{a}^{b} w(x)f(x)\ dt = f(\xi)\int_{a}^{b} w(x)\ dt
 * $$\displaystyle \int_{a}^{b} w(x)f(x)\ dt = f(\xi)\int_{a}^{b} w(x)\ dt
 * }

Find
Use IMVT to show that (5) in [[media:egm6341.s10.p2-2.png|Lecture p.2-2]] is equal to (1) in [[media:egm6341.s10.p2-3.png|Lecture p.2-3]]

 * {| style="width:100%" border="0" align="left"

= \frac{1}{n!} \frac{(x-x_0)^{n+1}}{(n+1)!}f^{(n+1)}(\xi)
 * $$\displaystyle R_n+1(x) = \frac{1}{n!} \int_{x_0}^{x} (x-t)^n f^{(n+1)}(t)\ dt

$$
 * }

for $$\quad \xi \in [x_0,x]$$

Solution
Because $$t \in [x_0,x]$$, thus $$ (x-t)^n \geqslant 0 $$, according to IMVT we have following equations:

 * {| style="width:100%" border="0" align="left"

= \frac{1}{n!} g(\xi)\int_{x_0}^{x} w(t)\ dt = \frac{1}{n!} f^{(n+1)}(\xi) \int_{x_0}^{x} (x-t)^n\ dt $$ $$ Int. $$ \int_{x_0}^{x} (x-t)^n\ dt $$, we have
 * $$ \displaystyle R_{n+1}(x) = \frac{1}{n!} \int_{x_0}^{x} \underbrace{(x-t)^n}_{w(t)} \underbrace{f^{(n+1)}(t)}_{g(t)}\ dt
 * $$ \displaystyle R_{n+1}(x) = \frac{1}{n!} \int_{x_0}^{x} \underbrace{(x-t)^n}_{w(t)} \underbrace{f^{(n+1)}(t)}_{g(t)}\ dt
 * $$\displaystyle (Eq. 1)
 * }
 * }

 * {| style="width:100%" border="0" align="left"

= \cancelto{o}{-\frac{(x-x)^{n+1}}{n+1}} + \frac{(x-x_0)^{n+1}}{n+1} = \frac{(x-x_0)^{n+1}}{n+1} $$ $$
 * $$ \displaystyle \int_{x_0}^{x} (x-t)^n\ dt = \left [ -\frac{(x-t)^{n+1}}{n+1} \right ]_{t=x_0}^{t=x}
 * $$ \displaystyle \int_{x_0}^{x} (x-t)^n\ dt = \left [ -\frac{(x-t)^{n+1}}{n+1} \right ]_{t=x_0}^{t=x}
 * $$\displaystyle (Eq. 2)
 * }
 * }

Use Eq.1 & Eq.2 we have :

 * {| style="width:100%" border="0" align="left"

$$ \displaystyle \Rightarrow  R_{n+1}(x) = \frac{1}{n!} \int_{x_0}^{x} (x-t)^n f^{(n+1)}(t)\ dt = \frac{(x-x_0)^{n+1}}{(n+1)!}f^{(n+1)}(\xi)
 * style="width:10%; padding:10px; border:2px solid #8888aa" |
 * style="width:10%; padding:10px; border:2px solid #8888aa" |

$$
 * style = |
 * }

for $$\quad \xi \in [x_0,x]$$

title: User:Egm6341.s10.team3.Min/HW1-x


text:
User:Egm6341.s10.team3.Min/HW1

= (5) Proof Taylor series by IMVT = Ref: Lecture Notes [[media:Egm6341.s10.mtg5.pdf|p.5-1]]

Problem Statement
See IMVT in [[media:Egm6341.s10.mtg2.pdf|Lecture p.2-3]]

 * {| style="width:100%" border="0" align="left"

$$ with $$ w(x)\geqslant 0 \quad \forall \ x \in [a,b] $$
 * $$\displaystyle \int_{a}^{b} w(x)f(x)\ dt = f(\xi)\int_{a}^{b} w(x)\ dt
 * $$\displaystyle \int_{a}^{b} w(x)f(x)\ dt = f(\xi)\int_{a}^{b} w(x)\ dt
 * }

Use IMVT to show that (5) in [[media:Egm6341.s10.mtg2.pdf|Lecture p.2-2]] is equal to (1) in [[media:Egm6341.s10.mtg2.pdf|Lecture p.2-3]]

 * {| style="width:100%" border="0" align="left"

= \frac{1}{n!} \frac{(x-x_0)^{n+1}}{(n+1)!}f^{(n+1)}(\xi)
 * $$\displaystyle R_n+1(x) = \frac{1}{n!} \int_{x_0}^{x} (x-t)^n f^{(n+1)}(t)\ dt

$$
 * }

for $$\quad \xi \in [x_0,x]$$

Solution
Because $$t \in [x_0,x]$$, thus $$ (x-t)^n \geqslant 0 $$, according to IMVT we have following equations:

 * {| style="width:100%" border="0" align="left"

= \frac{1}{n!} g(\xi)\int_{x_0}^{x} w(t)\ dt = \frac{1}{n!} f^{(n+1)}(\xi) \int_{x_0}^{x} (x-t)^n\ dt $$ $$ Int. $$ \int_{x_0}^{x} (x-t)^n\ dt $$, we have
 * $$ \displaystyle R_{n+1}(x) = \frac{1}{n!} \int_{x_0}^{x} \underbrace{(x-t)^n}_{w(t)} \underbrace{f^{(n+1)}(t)}_{g(t)}\ dt
 * $$ \displaystyle R_{n+1}(x) = \frac{1}{n!} \int_{x_0}^{x} \underbrace{(x-t)^n}_{w(t)} \underbrace{f^{(n+1)}(t)}_{g(t)}\ dt
 * $$\displaystyle (Eq. 1)
 * }
 * }

 * {| style="width:100%" border="0" align="left"

= \cancelto{o}{-\frac{(x-x)^{n+1}}{n+1}} + \frac{(x-x_0)^{n+1}}{n+1} = \frac{(x-x_0)^{n+1}}{n+1} $$ $$
 * $$ \displaystyle \int_{x_0}^{x} (x-t)^n\ dt = \left [ -\frac{(x-t)^{n+1}}{n+1} \right ]_{t=x_0}^{t=x}
 * $$ \displaystyle \int_{x_0}^{x} (x-t)^n\ dt = \left [ -\frac{(x-t)^{n+1}}{n+1} \right ]_{t=x_0}^{t=x}
 * $$\displaystyle (Eq. 2)
 * }
 * }

Use Eq.1 & Eq.2 we have :

 * {| style="width:100%" border="0" align="left"

$$ \displaystyle \Rightarrow  R_{n+1}(x) = \frac{1}{n!} \int_{x_0}^{x} (x-t)^n f^{(n+1)}(t)\ dt = \frac{(x-x_0)^{n+1}}{(n+1)!}f^{(n+1)}(\xi)
 * style="width:10%; padding:10px; border:2px solid #8888aa" |
 * style="width:10%; padding:10px; border:2px solid #8888aa" |

$$
 * style = |
 * }

for $$\quad \xi \in [x_0,x]$$

= (6) Show Taylor series by integration = Ref: Lecture Notes [[media:Egm6341.s10.mtg5.pdf|p.5-3]]

Problem Statement

 * {| style="width:100%" border="0" align="left"

$$ $$
 * $$\displaystyle f(x) = f(x_0) + \frac{(x-x_0)}{1!}\ f^{(1)}(x_0) + \int_{x_0}^{x} (x-t) f^{(2)}(t)\, dt
 * $$\displaystyle f(x) = f(x_0) + \frac{(x-x_0)}{1!}\ f^{(1)}(x_0) + \int_{x_0}^{x} (x-t) f^{(2)}(t)\, dt
 * $$\displaystyle (Eq. 1)
 * }
 * }

(i)Repeat int. by parts to reveal the following items with remainder

 * {| style="width:100%" border="0" align="left"

 * $$\displaystyle \frac{(x-x_0)^2}{2!}\ f^{(2)}(x_0) + \frac{(x-x_0)^3}{3!}\ f^{(3)}(x_0) $$

 * }

(ii)Assume (4)and (5) in [[media:Egm6341.s10.mtg2.pdf|Lecture p.2-2]] are true, do int. by parts one more time

Solution
(i)Int.$$\int_{x_0}^{x} (x-t){f^{(2)}(t)} dt $$ by parts in Eq 1:

 * {| style="width:100%" border="0" align="left"

\int_{x_0}^{x} \underbrace{(x-t)}_{U^\prime} \underbrace{f^{(2)}(t)}_{V}\, dt & = \left [ UV \right ]_{x_0}^x -  \int_{t=x} UV^\prime\, dt \\ & = \left [ -\frac{(x-t)^2}{2}\ f^{(2)}(t) \right ]_{t=x_0}^{t=x} + \underbrace{\int_{x_0}^{x} \frac{(x-t)^2}{2}f^{(3)}(t)\, dt}_{W1} \\ & = \cancelto{o}{-\frac{(x-x)^2}{2}\ f^{(2)}(x)} + \frac{(x-x_0)^2}{2}\ f^{(2)}(x_0) + W1\\ & = \frac{(x-x_0)^2}{2!}\ f^{(2)}(x_0) + W1\\ \end{align} $$ $$
 * $$ \displaystyle \begin{align}
 * $$ \displaystyle \begin{align}
 * $$\displaystyle (Eq. 2)
 * }
 * }

Use Eq 1, Eq 2, we have:
 * {| style="width:100%" border="0" align="left"

$$ $$
 * $$\Rightarrow \ f(x) = f(x_0) + \frac{(x-x_0)}{1!}\ f^{(1)}(x_0) + \frac{(x-x_0)^2}{2!}\ f^{(2)}(x_0) + \frac{1}{2!}\int_{x_0}^{x} {(x-t)^2}f^{(3)}(t)\, dt
 * $$\Rightarrow \ f(x) = f(x_0) + \frac{(x-x_0)}{1!}\ f^{(1)}(x_0) + \frac{(x-x_0)^2}{2!}\ f^{(2)}(x_0) + \frac{1}{2!}\int_{x_0}^{x} {(x-t)^2}f^{(3)}(t)\, dt
 * $$\displaystyle (Eq. 3)
 * }
 * }

Int. $$\int_{x_0}^{x} {(x-t)^2}f^{(3)}(t)\,dt $$ by part one more time in Eq 3:
 * {| style="width:100%" border="0" align="left"

\int_{x_0}^{x} \underbrace{(x-t)^2}_{U^\prime} \underbrace{f^{(3)}(t)}_{V}\, dt & = \left [ UV \right ]_{x_0}^x -  \int_{t=x} UV^\prime\, dt \\ & = \left [ -\frac{(x-t)^3}{3}\ f^{(3)}(t) \right ]_{t=x_0}^{t=x} + \underbrace{\int_{x_0}^{x} \frac{(x-t)^3}{3}f^{(4)}(t)\, dt}_{W2} \\ & = \cancelto{o}{-\frac{(x-x)^3}{3}\ f^{(3)}(x)} + \frac{(x-x_0)^3}{3}\ f^{(3)}(x_0) + W2\\ & = \frac{(x-x_0)^3}{3}\ f^{(3)}(x_0) + W2\\ \end{align} $$ $$ Use Eq 3, Eq 4, we have:
 * $$ \displaystyle \begin{align}
 * $$ \displaystyle \begin{align}
 * $$\displaystyle (Eq. 4)
 * }
 * }
 * {| style="width:100%" border="0" align="left"

$$\Rightarrow \ f(x) = f(x_0) + \frac{(x-x_0)}{1!}\ f^{(1)}(x_0) + \frac{(x-x_0)^2}{2!}\ f^{(2)}(x_0) + \frac{(x-x_0)^3}{3!}\ f^{(3)}(x_0) + \underbrace{\frac{1}{3!}\int_{x_0}^{x} (x-t)^3f^{(4)}(t)\, dt}_{Remainder} $$
 * style="width:10%; padding:10px; border:2px solid #8888aa" |
 * style="width:10%; padding:10px; border:2px solid #8888aa" |
 * style = |
 * }

(ii)Int. $$\int_{x_0}^{x} {(x-t)^n}f^{(n+1)}(t)\,dt $$ by part one more time:

 * {| style="width:100%" border="0" align="left"

\int_{x_0}^{x} \underbrace{(x-t)^n}_{U^\prime} \underbrace{f^{(n+1)}(t)}_{V}\, dt & = \left [ UV \right ]_{x_0}^x -  \int_{t=x} UV^\prime\, dt \\ & = \left [ -\frac{(x-t)^{n+1}}{n+1}\ f^{(n+1)}(t) \right ]_{t=x_0}^{t=x} + \underbrace{\int_{x_0}^{x} \frac{(x-t)^{n+1}}{n+1}f^{(n+2)}(t)\, dt}_{W} \\ & = \cancelto{o}{-\frac{(x-x)^{n+1}}{n+1}\ f^{(n+1)}(x)} + \frac{(x-x_0)^{n+1}}{n+1}\ f^{(n+1)}(x_0) + W\\ & = \frac{(x-x_0)^{n+1}}{n+1}\ f^{(n+1)}(x_0) + W\\ \end{align} $$ $$
 * $$ \displaystyle \begin{align}
 * $$ \displaystyle \begin{align}
 * $$\displaystyle (Eq. 5)
 * }
 * }

Use Eq 5, (4)& (5) in [[media:egm6341.s10.p2-2.png|Lecture p.2-2]], we have:
 * {| style="width:100%" border="0" align="left"

$$\displaystyle \Rightarrow \ f(x) = \underbrace{f(x_0) + \frac{(x-x_0)}{1!}\ f^{(1)}(x_0) + \cdots + \frac{(x-x_0)^{n+1}}{n+1}\ f^{(n+1)}(x_0)}_{P_{n+1}(x)} + \underbrace{\frac{1}{(n+1)!}\int_{x_0}^{x} (x-t)^{n+1}f^{(n+2)}(t)\, dt}_{R_{n+2}(x)} $$
 * style="width:10%; padding:10px; border:2px solid #8888aa" |
 * style="width:10%; padding:10px; border:2px solid #8888aa" |
 * style = |

 * }

title: User:Egm6341.s10.team3.Min/HW1


text:
User:Egm6341.s10.team1.toddmock

Links to home works are below

HW2

HW3

HW4

HW5

HW6

HW7

title: User:Egm6341.s10.team1.toddmock


text:
User:EmMain

Em Main

title: User:EmMain


text:
Haitian Creole/Vocabulary Review

 * This is a quiz of the vocabulary learned in Haitian Creole/Pronunciation, Haitian Creole/Articles, Haitian Creole/Basic Vocabulary, Haitian Creole/Basic Grammar and Haitian Creole/Articles.

Personal pronouns
Name the five personal pronouns, long and short forms.

Matching
Match the words on the left with the words/pictures on the right.

Creole to English
Give the meaning.

 * 1) Kay
 * 2) Dlo
 * 3) Manje (give two meanings)
 * 4) Bonjou
 * 5) Kijan ou rele?
 * 6) Kèk moun
 * 7) Yon timoun
 * 8) Kay yo

English to Creole
Translate.

 * 1) Thing
 * 2) Haitian Creole
 * 3) English
 * 4) This thing
 * 5) Thank you
 * 6) The thing I make
 * 7) Haiti
 * 8) Haitian

title: Haitian Creole/Vocabulary Review


text:
Haitian Creole/Vocabulary Review/Answer Key

Personal pronouns
Name the five personal pronouns, long and short forms.

Matching
Match the words on the left with the words/pictures on the right.

Creole to English
Give the meaning.

 * 1) Kay House(s)
 * 2) Dlo Water
 * 3) Manje (give two meanings) Food or eat
 * 4) Bonjou Good morning
 * 5) Kijan ou rele? What is your name?
 * 6) Kèk moun Some people
 * 7) Yon timoun A child
 * 8) Kay yo The houses or their house(s)

English to Creole
Give the word. The only word that must be capitalized is Ayiti.

 * 1) Thing bagay
 * 2) Haitian Creole kreyòl ayisyen
 * 3) English angle
 * 4) This thing bagay sa (a)
 * 5) Thank you mèsi
 * 6) The thing I make bagay mwen/m fè a
 * 7) Haiti Ayiti
 * 8) Haitian ayisyen


text: User talk:Egm6341.s10.team1.lei

title: User talk:Egm6341.s10.team1.lei